3(2x-4)+3x^2=6(x+6)

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Solution for 3(2x-4)+3x^2=6(x+6) equation: 


Simplifying
3(2x + -4) + 3x2 = 6(x + 6)

Reorder the terms:
3(-4 + 2x) + 3x2 = 6(x + 6)
(-4 * 3 + 2x * 3) + 3x2 = 6(x + 6)
(-12 + 6x) + 3x2 = 6(x + 6)

Reorder the terms:
-12 + 6x + 3x2 = 6(6 + x)
-12 + 6x + 3x2 = (6 * 6 + x * 6)
-12 + 6x + 3x2 = (36 + 6x)

Add '-6x' to each side of the equation.
-12 + 6x + -6x + 3x2 = 36 + 6x + -6x

Combine like terms: 6x + -6x = 0
-12 + 0 + 3x2 = 36 + 6x + -6x
-12 + 3x2 = 36 + 6x + -6x

Combine like terms: 6x + -6x = 0
-12 + 3x2 = 36 + 0
-12 + 3x2 = 36

Solving
-12 + 3x2 = 36

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 3x2 = 36 + 12

Combine like terms: -12 + 12 = 0
0 + 3x2 = 36 + 12
3x2 = 36 + 12

Combine like terms: 36 + 12 = 48
3x2 = 48

Divide each side by '3'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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